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4.8x^2-13x-48=0
a = 4.8; b = -13; c = -48;
Δ = b2-4ac
Δ = -132-4·4.8·(-48)
Δ = 1090.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{1090.6}}{2*4.8}=\frac{13-\sqrt{1090.6}}{9.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{1090.6}}{2*4.8}=\frac{13+\sqrt{1090.6}}{9.6} $
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